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ATQ, Let the distance be ‘d’ km So, 
And, 
From (i) and (ii), 
Let original speed be S km/h
[(S–12)×3]/12 = [(S–24)×7]/24 6(S–12) = 7(S–24) 6S–72 = 7S–168 S = 96 km/h Required distance = 96×(96–12)/12×3 = 96×7×3 = 2016 km
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