Question
A train travels from Station A to Station B at a speed
of 60 km/h and returns from Station B to Station A at a speed of 40 km/h. Find the average speed for the entire journey.Solution
Let the distance between A and B be D km. Time taken to travel from A to B = D / 60 hours. Time taken to travel from B to A = D / 40 hours. Average speed = 2 × (Speed1 × Speed2) / (Speed1 + Speed2) = 2 × (60 × 40) / (60 + 40) = 4800 / 100 = 48 km/h. Correct option: a
41.98% of 2200.031 + 15% of 3999.9 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
18.07 × (47.998 ÷ 12.03) + 59.78% of 150.14 – √(255.86) = ...
4.93% of 539.92-48% of 4700=?-8330.33
177.05 = 25.06% of 3631.97 + 16.02% of 3750.08 – ?3Â
? = 460.24 + 1057.97 – 14.992 Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 16.08 + 13.99 × 25.07
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
