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Let the distance between points 'P' and 'Q' be 'd' km. Let the speed of faster car and slower car be 'x' km/h and 'y' km/h, respectively. ATQ; {d/(x + y) } = 8 ........ (I) {d/(x - y) } = 40 ...... (II) So, 40 X (x - y) = 8 X (x + y) Or, 40x - 40y = 8x + 8y Or, 32x = 48y So, (x/y) = (3/2) So, speed of faster car = 60 X (3/2) = 90 km/h So, 'd' = (90 + 60) X 8 = 1200 For 'I': Distance between 'P' and 'Q' = 1200 km So, 'I' is false. For 'II': Distance covered by faster car when travelling in opposite directions = 1200 X (3/5) = 720 km So, 'II' is true. For 'III': Speed of faster car = 90 km/h And, speed of the slower car = 60 km/h Speed of faster car = 1.5 x speed of slower car So, 'III' is false.
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