Question
βEβ and βFβ are going from place βRβ to
place βSβ, which is 900 km apart. If βEβ started 2.5 hours after βFβ but both of them reached βSβ at the same time, then find the speed of βFβ. The difference between their speeds is 10 km/hr.Solution
ATQ, ATQ, Let the speed of βEβ be βzβ km/hr Therefore, speed of βFβ = (z β 10) km/hr According to the question, Since speed cannot be negative therefore, z = 60 Therefore, speed of βFβ = z - 10 = 50 km/hr
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