Question
A bike of length 2 meters moves past a man standing on
the sidewalk in 1 second. Another bike traveling twice as fast as the first one crosses another bike coming from the opposite direction in 2 seconds. Find the length of the second bike.Solution
ATQ, Speed of the first bike = (2/1) = 2 m/s Speed of the second bike = 2×2 = 4 m/s Relative speed = 2+4 = 6 m/s Total distance covered in 2 seconds = 6×2 = 12 meters Length of the second bike = 12−2 = 10 meters So, the length of the second bike is 10 meters.
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