Question
A ship, labeled as Ship A, departs from Mumbai to Pune
at 11:25 am, traveling at an average speed of 22.5 m/s. Simultaneously, Ship B travelled from Pune to Mumbai at 1:05 pm, maintaining an average speed of 17.5 m/s. Determine the time at which the two ships will meet, given that the distance between Mumbai and Pune is 615 km.Solution
ATQ, Speed of Ship A = 22.5 × 18/5 = 81 Km/h Speed of Ship B = 17.5 × 18/5 = 63 Km/h Distance travelled by Ship A till 1:05 am = 81 × (5/3) = 135 Km Relative speed of shipes = 81 + 63 = 144 Km/h Remaining distance to be travelled after 1:05 pm = 615 - 135 = 480 Km Time taken to cover 480 Km = 480/144 = 10/3 = 3 hours 20 minutes So the two shipes will meet each other at 1:05 + 3:20 = 4:25 pm
Central Depository Services Limited is promoted by which of the following:
The Gopatha Brahmana is linked to which Veda?
Consider the following pairs.
1. Krishna Wildlife Sanctuary – Karnataka
2. Wayanad Wildlife Sanctuary – Tamil Nadu
Which of the...
The 2nd phase of 36 ‘Saansad Khel Mahakumbh 2022-23’ has been inaugurated in which district of the state Uttar Pradesh?
Companies raise ECB because they get subsidy for raising capital from abroadÂ
According to the NABARD Rural Financial Inclusion Survey 2021-22, what percentage of an agricultural household’s income in India comes from cultivatio...
In the local language of Uttarakhand, which of the following is also referred to as Ragi?
If the de Broglie wavelength of an electron is equal to that of a proton, what can be concluded about their momenta?
WTO(World Trade Organization) is the successor of which organization?
Who built the Sun Temple in Odisha during the 12th Century AD?
