The two places are 60 km apart. A and B start walking towards each other at the same time and meet each other after 6 hours. Had A traveled with 2/3rd of his speed and B traveled with a double of his speed, they would have met after 5 hours. The speed of A is:
Let the speeds of ‘A’ and ‘B’ be ‘x’ km/h and ‘y’ km/h, respectively According to the question, (x + y) = (60/6) = 10 km/h Multiplying throughout by (2), we get (2x + 2y) = 20………. (I) Also, (2x/3) + 2y = 12 Or 2x + 6y = 36……. (II) Subtracting equation (I) from equation (II), we get ‘y’ = 4 km /h putting the value of y in the equation (ii) x = 6km /h
66   70    97    ?       238    274
...18   22    49    ?       190    226
...44 23 21 34.5 ? 167.5
...7200 7200 3600 1200 300 ?
...10                          15                          ?                    Â...
3, 4, 10, 33, 136, ?, 4116
Choose the correct alternative
21: 3 ∷ 574: ?
18    40     84    172     ?     700
...21, 37, 62, 98, 147, ?
32, 8, 4, ?, 3, 3.75
