Question
A and B are travelling towards each other with a speed
of 100 km/hr and 110 km/hr. If they started at same time and A covered 30 km less distance than B before meeting him, then find the distance between them before starting.Solution
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 100:110 = 10:11 Let the distance covered by A and B be 10x km and 11x km According to the question, 11x β 10x = 30 Or, x = 30 Therefore, distance between them before starting = 10x + 11x = 21x = 630 km
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