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Start learning 50% faster. Sign in nowSince, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 40:50 = 4:5 Let the distance covered by A and B be 4x km and 5x km According to the question, 5x – 4x = 20 Or, x = 20 Therefore, distance between them before starting = 5x + 4x = 9x = 180 km
Statement: X≤W=Y<P; W≥Z; Z ≥X
I. P>X
II. Y≥X
Statements: I < P = S ≥ O > W < E≤ G ≥ A
Conclusion
I: O ≤ P
II: G > O
Statements: J < K < M = L, D = E > F, F ≥ G < H = I > J
Conclusions:
I. D > K
II. I < L
III. E > J
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ K ≤ B
Conclusions:I. U ≥ E II. S > T
Statements:
A < W ≤ T < Y = O; V < S > K ≥ F > O
Conclusions:
I). W < S
II). Y ≥ K
...Statements: M > N = W; J < P = N; Y > P
Conclusions:
I. Y > W
II. M < Y
III. J > M
Statements: E & F, H # I, G $ F, E % D, G @ H
Conclusions:
I. D $ F
II. F @ I �...
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements: G ≤ D < F; C > D = E; A ≤ B < C; G > H
Conclusions:
I. C > H
II. F > A
III. E < B