Question
A and B are travelling towards each other with a speed
of 40 km/hr and 50 km/hr. If they started at same time and A covered 20 km less distance than B before meeting him, then find the distance between them before starting.Solution
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 40:50 = 4:5 Let the distance covered by A and B be 4x km and 5x km According to the question, 5x β 4x = 20 Or, x = 20 Therefore, distance between them before starting = 5x + 4x = 9x = 180 km
The value of 0.0486 Γ· 0.002 =Β
654.056 + 28.9015 × 44.851 – 43.129 =?

1555.5 + 1000.8 – 1354.3 = ? + 52
(β576 + β256)% of 1800 = ?
779 + 136 – 334 = 270 + 121 + ?
What will come in the place of question mark (?) in the given expression?
β144 X β324 + ? = 83 + 31 X β16
50 ÷ 2.5 × 64 + ? = 1520