Question
A and B are travelling towards each other with a speed
of 10 km/hr and 20 km/hr. If they started at same time and A covered 10 km less distance than B before meeting him, then find the distance between them before starting.Solution
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 10:20 = 1:2 Let the distance covered by A and B be x km and 2x km According to the question, 2x – x = 10 Or, x = 10 Therefore, distance between them before starting = x + 2x = 3x = 30 km
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
The speed of the boat in still water is 20% less than the speed of the boat in downstream. The time taken by the boat to cover 780 km distance in upstre...
(1709.87 ÷ 38.09) + (768.11 ÷ 23.87) + (6599.81 ÷ 88.06) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
25.22% of (59.9 × 8.01) + 69.97 =?Â
18.22 × 11.99 + 154.15 = ?
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
648.13 ÷ 35.86 + 28.88 × 13.13 – 39.92% of 900.19 = ?
(284.85 ÷ 15.09) x 2.22 + 51.17 = 157.69 - ?
