Question
Before servicing, a car runs at a speed of 25 km/hr while after servicing, it runs at a speed of 50 km/h. After servicing the car covers a certain distance in 8 hours. How much time would the car have taken to cover the same distance when it was not serviced?
More Algebra Questions
- Question 1
- If a + b + c = 10 and ab + bc + ca = 28, then find the value of a² + b² + c².
- If (a + b) = 11 and ab = 25, then find (a² + b²).
- Question 4
- If 2x+1, x+2, 2 and 5 are in proportion, then what is the mean proportional between 3.5(1-x) and 8(1+x)?
- If (x + y + z) = 14 and (xy + yz + zx) = 50, then find the value of (x² + y² + z²).
- If √b + (1/√b) = 11, then find the value of b + (1/b).
- If (x - y) = 1, then find the value of (x³ - y³ - 3xy).
- `sqrt(sqrt(2+sqrt(2+sqrt(2)) ... prop)` = ?
- The certain sum amounts to Rs11313.5 in 2(1/2) years at 12% p.a., interest compounded 10 months. The sum (in Rs) is:
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