Question
X started to run from point βAβ to βBβ at a
speed of 23 km/hr at 9:00 am and Y started to run from point βBβ to βAβ at a speed of 20 km/hr at 11:00 am. If they meet each other at 3:00 pm then find the distance between points βAβ and βBβ.Solution
Distance covered by X in 2 hours = 23 Γ 2 = 46 km Relative speed of X and Y = 23 + 20 = 43 km/hr Sum of distance covered by both in 4 hours = 43 Γ 4 = 172 km Total distance between points βAβ and βBβ = 46 + 172 = 218 km
?% of 320 = 40% of 40 Γ 5
(22Β² Γ 8Β²) Γ· (92.4 Γ· 4.2) =? Γ 32
42% of 400 + 38% of 800 + ?2 = 728
What will come in place of (?) in the given expression.
{(60% of 250) + β144} Γ· (3Β² - 4) = ?- What will come in place of (?) in the given expression.
β324 + β121 β β49 = ? Determine the simplified value of following expression:
0.998 + 0.882 + 0.12Β
β225 + 27 Γ 10 + ? = 320
(26)2 = {(20% of 40% of 18200) Γ· ?} Γ 1664 Γ· 128Β
(2 Γ· 3) Γ (4 Γ· 12) Γ (? Γ· 10) Γ 45 Γ (1 Γ· 5) = (? Γ· 6) + (2 Γ· 5)
What is the value of 143Β + 163Β + 183Β + β¦ + 303?