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Since, the speed of the bike increases by 4 km/hr after every 1 hour, therefore the bike will travel 4 km extra after every 1 hour. Therefore, distance travelled by the bike in 1st hour = 20 km Distance travelled by the bike in 2nd hour = 20 + 4 = 24 km Distance travelled by the bike in 3rd hour = 24 + 4 = 28 km This form an AP i.e. 20, 24, 28………distance travelled in 12th hour Therefore, total distance travelled by the bike in 12 hours = sum of the AP Distance travelled in 12 hours = (n/2){2a + (n – 1)d} Where n = number of terms = 12, a = 1st term = 20 and d = common difference = 12 Therefore, distance travelled in 12 hours = (12/2){2 × 20 + (12 – 1) × 4} = (12/2)(40 + 44) = 504 km
123% of 3825 +2745 =11800 - ?
...? = (7.11/2.12) + (10.88/4.09) + (45.12/11.98)
(239.89 ÷ 3.89) – (144.01 ÷ 5.73) = ?2
2660.03 ÷ 69.98 x 49.9 = ? + 10.32
If 'a' = √1024 ÷ 4 + 96 ÷ 3 + 85 ÷ 17 and 'b' = 30 × 18 ÷ 6 - 7² + 110, then find the value of (a + b).
...233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
? = 22.08 + 13.99 × 22.07
? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
30.05% of 360.05 – 25.15% of 99.99 × 3.02 = ?