Question
Ajay and Vishal left the place ‘X’ with different
speeds which are in the ratio 3:2 respectively. Ajay left the place 30 seconds after Vishal. If after 54 seconds of the departure of Vishal, Ajay is 50 meters apart from Vishal, then find the speed of Vishal.Solution
Let the speeds of Ajay and Vishal be 3x and 2x km/hr respectively. Distance covered by Vishal in 54 seconds = 2x x (5/18) x 54 = 30x m Distance covered by Ajay in 30 seconds = 3x x (5/18) x 30 = 25x m According to the question, => 30x – 25x = 50 => x = 10 Therefore the speed of Vishal = 2x = 20 km/hr
More Time and distance Questions
- Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN
