Question
If a person walks 25% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 420 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 420 km According to the question 420/x – 420/(5x/4) = 90/60 420 x [(5 – 4)/5x] = 3/2 Therefore, x = 420 x (1/5) x (2/3) = 56 km/hr
For the cumulative distribution function
the upper quartile point is
The probability of getting a total of 7 on two dice thrown together is:
If the odds in favour of any random event A are 5 : 6, then the odds against the event are:
If price-quantity are related for base year (0) and current year (1) are
∑ : p0q0 = 260,∑ : p1q0 = 395,∑ : p0q1 = 264,∑ : p1q1 = 422, t...
The Pension Fund Regulatory and Development Authority (PFRDA) launched Retirement Income Schemes (RIS) under NPS in May 2026. Up to what age can NPS sub...
Using the method of semi-averages, secular trend is measured when:
Fundamental principles of design of experiment are
(I) Randomization
(II) Replication
(III) Local control
Which option is correct?
The mean and median of the distribution is 12 and 15. Then the mode equals to:
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