Question
A boy goes to his school at 1/6th of the speed at which
he returns from his school. Average speed during the whole trip (i.e. one round) is 24 km/h. What is the speed of the boy while he was going to his school?Solution
Speed while going to school = x/6 Speed while returning = x Average speed = (2 × S1 × S2)/(S1 + S2) => 24 = (2 × x/6 × x)/(x/6 + x) => x = 84 Speed while going to school = 84/6 = 14 km/hr
More Time and distance Questions
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 × 9.05 = ?
(11.75)2 - 49.99% of 120 - ? = (8.23)2
(√ (5475.5) + √ (1024.2)) - √ (4095.8) ÷ (√ (143.9) × √ (15....
? × [(16.87) 2 – (6.98) 2 ] = 5.04× 191.11
120.982-√675×5+1422.20÷9.02=?
[(5/9 of 719.87) + (59.73% of 450.31)] ÷ (√168.79 - 3/4 of 63.94) = ?
√624.98 - ? = √(62.30 + 13.99 – 2.93)
3245.69 + ? – 3112.48 = 2654.87 – 2412.92
44.89% of 600.25 + (29.98 × 5.67) + (√1940 – 10.29) = ?2
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
