Question
A boy goes to his school at 1/6th of the speed at which
he returns from his school. Average speed during the whole trip (i.e. one round) is 24 km/h. What is the speed of the boy while he was going to his school?Solution
Speed while going to school = x/6 Speed while returning = x Average speed = (2 × S1 × S2)/(S1 + S2) => 24 = (2 × x/6 × x)/(x/6 + x) => x = 84 Speed while going to school = 84/6 = 14 km/hr
More Time and distance Questions
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
75.22 of 219.98% + 359.99 ÷ 18.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?
What approximate value will come in place of the question mark (?) in the following question?
(2160.23 ÷ 35.98) + (600.32 ÷ 23.9) + 1744.11 = ?
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
(5/9 of 2700.11) + (49.78% of 143.88) - (2/7 of 489.89) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
