Distance travelled by the first car in 5 hours = 60 × 5 = 300 km Remaining distance = 550 - 300 = 250 km Time for both cars to meet = distance/(relative speed ) = 250/(60+40) = 250/100 = 21/2 hrs = 2 hrs 30 min ∴ Both the cars will meet after 2 hrs 30 min means (10 am + 2 hrs 30 min) = 12 hrs 30 min
(1.69) -1.5 = ?
If (7/5)4 x (7/5)6 = (7/5)(2x+2) then x is equal to
If 2x = 3y = 6-z, then (1/x) + (1/y) + (1/z) =?
The value of ‘x’ in the given below equation is.
0.5 ̅ + 0.7 ̅ + 0.9 ̅ + 0.3 ̅ = x
Find the value of 56× 59÷ 514= ?
If (15000) 4 = 50.625
The value of ((1024)n/5× 42n+1)/( 16n × 4n-1)
(0.04)-2.5= ?