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    Question

    If 2x = 3y = 6-z, then

    (1/x) + (1/y) + (1/z) =?
    B 1 Correct Answer Incorrect Answer
    C 2 Correct Answer Incorrect Answer
    D 3 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let 2x = 3y = 6-z = k   So,   2 = k(1/x) , 3 = k(1/y) and 6 = k(-1/z)   k(1/x) × k(1/y) = k(-1/z) [:. 2 x 3 = 6]   k(1/x + 1/y) = k(-1/z)   (1/x) + (1/y) = (-1/z)   (1/x) + (1/y) + (1/z) = 0 

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