Question
If 2x = 3y = 6-z, then
(1/x) + (1/y) + (1/z) =?Solution
Let 2x = 3y = 6-z = k  So,  2 = k(1/x) , 3 = k(1/y) and 6 = k(-1/z)  k(1/x) × k(1/y) = k(-1/z) [:. 2 x 3 = 6]  k(1/x + 1/y) = k(-1/z)  (1/x) + (1/y) = (-1/z)  (1/x) + (1/y) + (1/z) = 0Â
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