Question
Simplify: (β3 + 1)/(β3 β 1) + (β3 β
1)/(β3 + 1)Solution
Let a = β3, b = 1. Expression = (a + b)/(a β b) + (a β b)/(a + b) = [(a + b)Β² + (a β b)Β²] / (aΒ² β bΒ²) (a + b)Β² = aΒ² + 2ab + bΒ² (a β b)Β² = aΒ² β 2ab + bΒ² Sum = 2aΒ² + 2bΒ² Denominator = aΒ² β bΒ² So expression = 2(aΒ² + bΒ²)/(aΒ² β bΒ²) Here aΒ² = 3, bΒ² = 1 = 2(3 + 1)/(3 β 1) = 2Γ4 / 2 = 4.
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