Question
Simplify:Β (2β75 + 3β48 - β27) /
β3Solution
β75 = 5β3 So 2β75 = 10β3 β48 = 4β3 So 3β48 = 12β3 β27 = 3β3 Numerator: 10β3 + 12β3 - 3β3 = 19β3 Now, 19β3 / β3 = 19
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