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    Question

    Find the value of 27 ÷ 2 of 16 of [6 ÷ 8 of (6 ÷ 2 +

    5)] + (10 ÷ 2.5 + 1)
    A 14 Correct Answer Incorrect Answer
    B 19 Correct Answer Incorrect Answer
    C 27 Correct Answer Incorrect Answer
    D 31 Correct Answer Incorrect Answer

    Solution

    ATQ, = 27 ÷ 2 of 16 of [6 ÷ 8 of (6 ÷ 2 + 5)] + (10 ÷ 2.5 + 1) = 27 ÷ 2 of 16 of [6 ÷ 8 of 8] + (10 ÷ 2.5 + 1) = 27 ÷ 2 of 16 of [6 ÷ 64] + (4 + 1) = 27 ÷ 2 of 16 of [6 ÷ 64] + 5 = 27 ÷ [2 of 16 of (6 ÷ 64)] + 5 = 27 ÷ [2 of (16 × 6/64)] + 5 = 27 ÷ [2 of (96/64)] + 5 = 27 ÷ [2 of 3/2] + 5 = 27 ÷ 3 + 5 = 9 + 5 = 14

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