Question
Find the value of {(3125) (n/5) Â Ă— 5
(2n + 2) }/ {25 n  × 5 (n - 1) } ÂSolution
{(3125) (n/5) × 5(2n + 2)}/ {25n × 5(n - 1)}  = 5(n + 2n + 2) / 5(2n + n - 1) = 5(3n + 2)/5(3n - 1) = 5(3n + 2- 3n + 1) = 53 = 125.
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