Question
Solution
3β11, β7, 4β45 Here β7 = 4β49 4β4 5 Β < 4 β49 Now 4β4 5 Β > 3β11 since 3rd power of 45 will be greater than 4th power of 11 i.e 14631 An so β7 > 4β45 > 3β11
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