Question
Solution
3β11, β7, 4β45 Here β7 = 4β49 4β4 5 Β < 4 β49 Now 4β4 5 Β > 3β11 since 3rd power of 45 will be greater than 4th power of 11 i.e 14631 An so β7 > 4β45 > 3β11
Simplify the following trigonometric expression:
...
12 cos 68oΒ cosec 22oΒ - 3 cot 72oΒ cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
β65 of 14.97 + β50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 Γ· 13.89 X 8.13 + ? = 11.852Β
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 β ?