Question
Solution
3β11, β7, 4β45 Here β7 = 4β49 4β4 5 Β < 4 β49 Now 4β4 5 Β > 3β11 since 3rd power of 45 will be greater than 4th power of 11 i.e 14631 An so β7 > 4β45 > 3β11
βABC and βDEF are similar and their areas are respectively 121 cm2 and 144 cm 2 . If EF = 24 cm BC is?
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The radius of a circle is 25 cm, and the length of the chord is 14 cm. Find the distance between the chord and the centre of the circle.Β Β
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