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      Question

      Rs. 2,800 is invested in three parts all at simple

      interest of 5% p.a. These three parts are invested randomly for 1 year, 2 years and 4 years such that the interest received from the given three parts after desired period of investment is same. Find the difference between the smallest and the largest part of the investment.
      A Rs. 1,200 Correct Answer Incorrect Answer
      B Rs. 960 Correct Answer Incorrect Answer
      C Rs. 840 Correct Answer Incorrect Answer
      D Rs. 1,080 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Let the amount invested in three parts be Rs. ‘p’, Rs. ‘q’ and Rs. ‘r’ ATQ; (p × 0.05 × 1) = (q × 0.05 × 2) = (r × 0.05 × 4) Or, p = 2q = 4r Let p = 2q = 4r = ‘4t’ So, p = 4t
      q = 2t
      r = t So, p + q + r = 2800 Or, 4t + 2t + t = 2800 Or, 7t = 2800 Or, t = 400 So, required difference = 4t − t = 3t = 3 × 400 = Rs. 1,200

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