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    Question

    Karan invested Rs. (x + 250) in Scheme A at a simple

    interest rate of 25% p.a. for 2 years, and the interest received is Rs. 1000. He then invested Rs. 3x in Scheme B at R% p.a. simple interest, and the total amount received from Scheme B after 3 years is Rs. 9030. Find the value of R.
    A 36% Correct Answer Incorrect Answer
    B 24% Correct Answer Incorrect Answer
    C 42% Correct Answer Incorrect Answer
    D 20% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    For Scheme A, SI = P × R × T / 100 1000 = (x + 250) × 25/100 × 2 1000 = (x + 250) × 0.5 x + 250 = 1000 / 0.5 x + 250 = 2000 x = 1750 For Scheme B, Amount invested = 3x = 3 × 1750 = Rs. 5250 Total amount after 3 years = Rs. 9030 Simple interest from Scheme B = 9030 – 5250 = Rs. 3780 Now, 3780 = 5250 × R/100 × 3 3780 = 157.5R To avoid decimals in calculation, rewrite 5250 × 3 / 100 first: (5250 × 3) / 100 = 157.5 So, 3780 = 157.5R R = 3780 / 157.5 R = 24%

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