Question
Ramesh invested Rs. (x + 200) in Scheme A at a simple
interest rate of 20% p.a. for 2 years, and the interest received is Rs. 800. He then invested Rs. 3x in Scheme B at a rate of R% p.a. (simple interest), and the total amount received from Scheme B after 2 years is Rs. 7020. Find the value of R.Solution
According to the question, For Scheme A, SI = P × R × T / 100 800 = (x + 200) × 20/100 × 2 800 = (x + 200) × 0.4 x + 200 = 800 / 0.4 x + 200 = 2000 x = 1800 For Scheme B, Amount invested = 3x = 3 × 1800 = Rs. 5400 Total amount after 2 years = Rs. 7020 Simple interest from Scheme B = 7020 – 5400 = Rs. 1620 Now use SI formula: 1620 = 5400 × R/100 × 2 1620 = 108R R = 1620 / 108 R = 15%
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â
? + 154.99 – 110.01 = 30.01 × 4.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A and B can complete a task together in 30 days, while B alone takes 60 days to finish it. A began working alone and left after ‘x’ days, after whic...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(21.02%  of 600.15 ) × 14.95 = ? 2 + 29.99 × 3456 ÷ 1152
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 460.24 + 1057.97 – 14.992 Â
? % of 759.96 + 932.99 = 1237.01
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
