Question
Karan invested Rs. (x + 500) in a scheme A offering
simple interest of 16% p.a., and the interest received after 2 years is Rs. 640. He invested Rs. 2x in scheme B at a rate of R% p.a. in simple interest, and the total amount received in scheme B after 3 years is Rs. 6240. Find the value of R.Solution
For Scheme A: SI = P × R × N / 100 640 = (x + 500) × 16 × 2 / 100 640 = (x + 500) × 0.32 x + 500 = 2000 x = 1500 For Scheme B: Amount invested = 2 × 1500 = 3000 6240 – 3000 = 3000 × R × 3 / 100 3240 = 90R R = 3240 / 90 = 36%
What is the value of (152+82) ÷17
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?560 ÷ 14 × 3 – 25 = ?
What will come in the place of question mark (?) in the given expression?
35 X 72 + 35 X 28 = ? X √16
What will come in the place of question mark (?) in the given expression?
{(5400 ÷ 30 of 12) × 20 + 200} = ? % of 1000
8 × 12 + 110 ÷ 5 = 72 + ?
25% of 1000 + 10% of 150 – 22 × ? = 45
Determine the simplified value of the given mathematical expression.
324² × 36 ÷ 18⁵ × 1120 =?
120% of 25 + 80 X 2 = ?2 - 6
