Question
A man invested Rs. 12000 in bank A at 10% p.a. compound
interest for three years. The interest received from the bank A is Rs. 1472 more than the interest on some other amount invested in bank B at 8% simple interest for 5 years. What is the amount invested in bank B?Solution
Compound interest earned from bank A = 12000 × [(1 + 10/100) 3  – 1] = 12000 × 0.331 = Rs. 3972
Simple interest earned from bank B = 3972 – 1472 = Rs. 2500
Let, the amount invested in the bank B be Rs. x.
So, 2500 = (x * 8 * 5)/100
250000 = 40x,
x = Rs. 6250
Therefore, the amount invested in the bank B = Rs. 6250
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