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ATQ, Let the sum invested by ‘X’ and ‘Y’ be Rs. 7x and Rs. 4x, respectively. According to the question, 7x – 4x = 6300 Or, 3x = 6300 Or, x = 2100 Therefore, sum invested by ‘Y’ in scheme ‘N’ = 4x = Rs. 8400 Amount received by ‘Y’ = 8400(1 + 40/100)² = Rs. 16464
1120 / √x = 80 Then x = ?
18 * 9 + 25% of 120 + 50% of 200 = ?
Simplify-
x + 3(y + x – 2) – (x + y).
28 × 3.5 +25 × 3.2 = ? - 62
108 ÷ ? + 156 ÷ √144 = √64 × 2
17.8 + 3/7 of 89.6 = ?
Find the value of ‘a’ in the following expression:
12 × a × 24 ÷ 8 + 72 – 46 = 170
16/15 of 21/28 of 321.5 = ?
? = 15% of 2400 + 140% of 4200 – 12 3