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Let the amount invested in scheme A be ₹x. Then, the amount invested in scheme B is ₹50,000 - x. Interest from scheme A (simple interest) = P × R × T / 100 = x × 12 × 1 / 100 = 0.12x. Interest from scheme B (compound interest) = P(1 + R/100)^T - P = (50,000 - x)(1 + 10/100) – (50,000 - x) = (50,000 - x)(1.1) - (50,000 - x) = (50,000 - x) × 0.1. The total interest from both schemes is ₹5,800, so: 0.12x + (50,000 - x) × 0.1 = 5,800. 0.12x + 5,000 - 0.1x = 5,800, 0.02x = 800, x = 800 / 0.02 = ₹40,000. Thus, the amount invested in scheme A is ₹40,000. Correct option: d
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?
(3/7) x 868 + 25% of 240 = (? + 65)
[{(1296 ÷ 18) ÷ 12} ÷ 6] + 82 + √625 = ?
∛857375 + ∛91125 = ? + √6889
5.5 × 3.2 × 2.3 = ?
(92.03 + 117.98) ÷ 14.211 = 89.9 – 30.23% of ?
Evaluate: {2 x (0.718 + 0.982) + 0.008 of 5000}