Question
Mohan invests ₹8,000 each in two different schemes,
'A' and 'B', for a duration of 2 years. Scheme 'A' provides compound interest at an annual rate of 16% (compounded yearly), while Scheme 'B' offers simple interest at the same annual rate of 16%. Calculate the difference in the total interest earned from Scheme 'A' compared to Scheme 'B'.Solution
When Rs. 'P' each is invested at 'R'% p.a. for 2 years on compound interest and simple interest, then difference between interest = P x (R/100) 2 Therefore, required difference = 8,000 x (16/100) 2 = 8,000 x (256/10,000) = Rs. 204.8
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
456.9 + 328.10 - 122.98 = ? + 232.11
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
256.12 ÷ 7.92 + 26.11 × 7.82 – 44.09 = ?2
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