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      Question

      A vessel contains 120 liters of a mixture of milk and

      water, with 75% of it being milk. If 30 liters of this mixture is replaced by 30 liters of water, what is the new percentage of milk in the mixture?
      A 56.25% Correct Answer Incorrect Answer
      B 60% Correct Answer Incorrect Answer
      C 65.55% Correct Answer Incorrect Answer
      D 70% Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Amount of milk in the initial mixture = 75% of 120 liters = 90 liters Amount of water in the initial mixture = 120 - 90 = 30 liters When 30 liters of the mixture is replaced by water, the amount of milk removed = 75% of 30 liters = 22.5 liters So, the remaining milk = 90 - 22.5 = 67.5 liters The total volume of the mixture remains 120 liters, but now the water is 30 liters (original) + 30 liters (added) = 60 liters Percentage of milk in the new mixture = (67.5/120) × 100 = 56.25% ≈ 56%

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