Question
A person invests ₹25,000 in a scheme offering 12%
annual simple interest. After 3 years, the amount is withdrawn and some amount invested in another scheme offering 15% annual simple interest. If the total interest earned after 8 years is ₹13,500, find the principal amount invested in the second scheme.Solution
Interest from the first scheme: Simple Interest = P × R × T / 100 = 25,000 × 12 × 3 / 100 = ₹9,000 Total interest earned = ₹13,500 Interest from the second scheme = ₹13,500 - ₹9,000 = ₹4,500 Let the principal in the second scheme be P. Simple Interest = P × 15 × 5 / 100 = P × 75 / 100 = 3P / 4 3P / 4 = 4,500 P = 4,500 × 4 / 3 P = ₹6,000 Thus, the principal invested in the second scheme is ₹6,000.
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
9.99% of 19.86% of 30.23% of (11999.84 × 9.68) = ?
120.982-√675×5+1422.20÷9.02=?
40.93√? + √6625 + √6920 + √? = 205.7542`xx` 7.654
(239.88 ÷ 7.86) + (107.78 ÷ 6.06) of 3.18 – (12.12 × 5.3) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
5999.93 ÷ 60.005 × 70.002 = ? × 24.9
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
If 4tan4 + 9 – 12tan2 = 0, then find the value of cot.
