Question
A man invested Rs. 'B' at simple interest of 18% and Rs. 'B + 4000' at simple interest of 14% p.a., for 4 years each. If the interest earned from both investments is the same, then find the sum invested at the lower rate of interest.
Or, 7.2B = (B+4000)×5.6 Or, 7.2B = 5.6B+22400 Or, 1.6B = 22400 Or, B = 14000 So, sum invested at lower interest = 14000 + 4000 = Rs. 18,000More Simple and compound interest Questions
- The difference of S.I and C.I on an amount of Rs. 40000 for 2 years is Rs. 64. What is the rate of interest?
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- A sum of money becomes three times itself in 12 years at simple interest. What is the rate of interest?
- Ramesh deposited Rs. 10,500 at 18% per annum for 2 years and Rs. 7,200 at 22% per annum for 4 years. Calculate the total simple interest he received.
- Rs. (n + 400) invested on simple interest amounts to Rs. 3,200 and Rs. 3,800 in 4 years and 6 years, respectively. Find the value of 'n'.
- Veeru invested Rs. 3100 at 20% p.a. simple interest for 3 years. After 3 years, he invested the amount received by him at the 20% p.a. compound interest, c...
- Rs. (n + 300) invested on simple interest amounts to Rs. 3,000 and Rs. 3,600 in 4 years and 6 years, respectively. Find the value of 'n'.
- Rs. 3,000 is deposited in a savings account at a simple interest rate of 30% per annum for 4 years. The total money is then reinvested in stocks offering c...
- A certain amount becomes seven times of itself in 24 years at a certain rate of simple interest p.a. In what time will it become sixteen times of itself at...
- Asha borrowed Rs. 4000 at R% S.I. and Rs. 6000 at (R + 2)% S.I. for 3 years. If the total interest was Rs. 1860, find the rate on Rs. 6000.
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