Question
Meera had Rs. 3500 with her. She invested Rs. ‘c’ at
14% p.a. simple interest for 6 years and the remaining sum at 20% p.a. compound interest, compounded annually for 2 years. If the total interest received by her is Rs. 2300, then find the value of ‘c’.Solution
ATQ, Simple interest received by Meera = (c × 14 × 6)/100 = Rs. 0.84c Compound interest received by Meera = (3500 – c)(1 + 20/100)² – (3500 – c) = Rs. 1.44(3500 – c) - (3500 - c) = Rs. 0.44(3500 - c) According to the question, 0.84c + 0.44(3500 – c) = 2300 Or, 0.84c + 1540 - 0.44c = 2300 Or, 0.4c = 2300 - 1540 Or, 0.4c = 760 Or, c = 760 / 0.4 = 1900
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?
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