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    Question

    In the question, three series I, II and III are given.

    Find the value of x, y and z to establish the correct relation among them and choose the correct option. (I) 17, 36, 59, 88, 119, x (II) 5, 11, 29, 59, 101, y (III) 42, 43, 51, 60, 124, z
    A x < y < z Correct Answer Incorrect Answer
    B x > y > z Correct Answer Incorrect Answer
    C x < y > z Correct Answer Incorrect Answer
    D x > y < z Correct Answer Incorrect Answer
    E x = y > z Correct Answer Incorrect Answer

    Solution

    Series I: 17 + 19 = 36 36 + 23 = 59 59 + 29 = 88 88 + 31 = 119 119 + 37 = 156 So, x = 156 Series II: 5 + 6 × 1 = 11 11 + 6 × 3 = 29 29 + 6 × 5 = 59 59 + 6 × 7 = 101 101 + 6 × 9 = 155 So, y = 155 Series III: 42 + 12 = 43 43 + 23 = 51 51 + 32 = 60 60 + 43 = 124 124 + 52 = 149 So, z = 149 So, x > y > z

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