Question
R' invested an amount of Rs. 'r' for a duration of 4
years, while 'S' invested Rs. 6000 for 18 months. The ratio of their respective profits is 16:9. Determine the sum of the investments made by 'R' and 'S' from the given options: I. Rs. (2r + 2000) II. Rs. (3r – 2000) III. Rs. {(5r/2) + 500)Solution
ATQ, 48x/(18 × 6000) = 16/9 Or, 27r = 18 × 6000 Or, r = Rs.4000 Therefore, sum of the investment made by both of them = (4000 + 6000) = Rs.10000 For I: (2r + 2000) = (2 × 4000 + 2000) = Rs.10000 Therefore, I can be the answer. For II: (3r – 2000) = (3 × 4000 – 2000) = Rs.10000 Therefore, II can be the answer For III: {(5r/2) + 500)} = {(20000/2) + 500} = Rs.10500 Therefore, III cannot be the answer.
44.84% of 799.94 + (625.21 ÷ 24.91) – √(224.77) = ?
24.11 × 5.98 + 25.03 × 3.12 – 34.99 + 96.9 × 5.02 =?
(8.86)² × (15.01)² ÷ √624.99 = 9?
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
( 1728)1/3 × 10.11 × 3.97 ÷ 8.32 = ? + 15.022
(17.98% of 249.99) - 4.998 = √?
? + 96.18 – 15.02 = 118.98 + 31.09
Find the approximate value of Question mark(?). No need to find the exact value.
(639.78 ÷ 15.96) × 5 + 30.14% of 349.88 – √(224.95) ÷ 5...
9214.39 - 6843.57 + 8435.22 + ? = 17620.47