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    Question

    If the difference between the simple interest and

    compound interest, compounded annually, received on a principal amount of Rs. 25000 at an interest rate of (a + 2)% for 2 years is Rs. 160, calculate the time required for an investment at a simple interest rate of (a + 4)% per annum to double.
    A 15 yrs Correct Answer Incorrect Answer
    B 25 yrs Correct Answer Incorrect Answer
    C 18 yrs Correct Answer Incorrect Answer
    D 10 yrs Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Difference between the compound interest and simple interest received for 2 years = P(R/100)2 where P = sum invested, R = rate of interest According to the question, 25000 ├Ч {(a + 2)2/10000} = 160 Or, (a + 2)2 = 1600000/25000 = 64 Or, a + 2 = 8 (Since, rate cannot be negative) Or, a = 6 Let, time required to double a certain sum i.e. Rs. 's' = t years Rate of interest = (a + 4) = 10% p.a. So, {(s ├Ч 10 ├Ч t)/100} = 2s тАУ s = s Or, 10t = 100 Or, t = 10 Required time = 10 years

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