Question
Sunil invested Rs. ‘4x’ in scheme ‘A’ offering
simple interest of 25% p.a. and reinvested the interest earned from scheme ‘A’ at the end of 4 years in scheme ‘B’ offering compound interest of 20% p.a. compounded annually. If total amount received from scheme ‘B’ after 2 years is Rs. 4320, then find the value of ‘12x’.Solution
According to question; 1.44 × {0.25 × 4 × 4x} = 4320 Or, {0.25 × 4 × 4x} = 3000 Or, x = 750 So, 12x = 12 × 750 = 9000
If 0 ≤ θ ≤ 90°, and sec107 θ + cos107 θ = 2, then. (secθ + cosθ) is equal to:
If -5 ≤ x ≤ 3 and -1 ≤ y ≤ 0, then the minimum value of 2y – 3x is:
If sec θ + tan θ = m(> 1), then the value of sin θ is (0° < θ < 90°)
If x4 + 2x3 + ax2 + bx + 9 is a perfect square, where a and b are positive real numbers, then the value of a and b are
If α and β are the roots of equation x2 – x + 1 = 0, then which equation will have roots α3 and β3?
...If 8x2 + y2 − 12x − 4xy + 9 = 0, then the value of (14x − 5y) is :
If a + 1/a = -2 then the value of a1000 + a- 1000 is
Quantity I – 3
Quantity II – 254
If > 0 and < 0
Solve the cubic equation, x³ − 7x² + 14x − 8 = 0 and Find all real roots.
The value of x which satisfies the equation (x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) ...
Relevant for Exams:
