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Let, the amount be Rs. P. P[(1 + 20/100)2 – 1] – P × 20% × 2 = 240 P × 0.44 – P × 0.4 = 240 P × 0.004 = 240 P = 240 ÷ 0.004 = Rs. 6000 Therefore, required interest = 6000 × 10% × 2 = Rs. 1200
If x + y = 2 and 1/x + 1/y = 18/15, then find the value of (x3 + y3)?
Given that (3a + 7b = 54) and (ab = 24), determine the value of (9a2 + 49b2).
If 5x - 13xy + 6y = 0, find x : y.
Find the 36th term of the series 25, 29, 33……
If (a - b - c) = 6, and (ab - bc + ca) = 117, then find the value of (a2 + b2 + c2)
(44² × 16²) ÷ (184.8 ÷ 8.4) =? × 64
If 27 (x+y)³ − 8(x−y)³ = (x + 5y) (Ax² + By² + Cxy), then what is the value of (A+B-C)?
48 24 24 48 ? 1536
...If (x+1/x)2 = 3 Then the value of
x96 + x66 + x42 + x18 + x12 + 1 is