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Let, the amount be Rs. P. P[(1 + 10/100)2 – 1] – P × 10% × 2 = 120 P × 0.21 – P × 0.2 = 120 P × 0.01 = 120 P = 120 ÷ 0.01 = Rs. 12000 Therefore, required interest = 12000 × 10% × 2 = Rs. 2400
∛21952 × 44 = ? × 14
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
464 + 181 +? = (154 × 25) - (15) 2
(360 - ?)/(25% of 96) = 13
(25 + 12) x 6 + 34 = ? + 18
16 × 14 + 30 × 21 = 14 × ?
√ (122 + ? + 65) = 14
12.5% of (100 + ?) = 40