Question
The difference between compound interest and simple
interest at rate of 14% per annum for 2 years is Rs. 294. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.Solution
Let, the amount be Rs. P. P[(1 + 14/100)2 – 1] – P × 14% × 2 = 294 P × 0.2996 – P × 0.28 = 294 P × 0.0196 = 294 P = 294 ÷ 0.0196 = Rs. 15000 Therefore, required interest = 15000 × 10% × 2 = Rs. 3000
What will come in place of (?) question mark in the following expression.
5(1/4) + 3(1/2) - 2(1/8) = ?
What will come in the place of question mark (?) in the given expression?
(352 - ?) ÷ 8 = 2.5 X 40 - 444 ÷ 6
Evaluate
64 ÷ 4 of 5 of [10 ÷ 5 of (9 ÷ 3 + 2)] + (9 ÷ 3 + 1)
What will come in place of (?) question mark in the following expression.
 (√1296 ÷ √36) × ? = 120
- What will come in place of (?) in the given expression.
√324 + √121 – √49 = ? 135.37 – 50.24 + 629.09 – 199.50 = ? – 214.68 + 42.65
Simplify: 240 ÷ (5×3) + 18×2 − 7
18, 25, 33, 42, 52, 63, ?
2.4 of 7.2 of 1/57.6 of 4200 = ?
255 × 8 + 386 × 5 =? % of 7940
