Question
The difference between compound interest and simple
interest at rate of 14% per annum for 2 years is Rs. 294. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.Solution
Let, the amount be Rs. P. P[(1 + 14/100)2 – 1] – P × 14% × 2 = 294 P × 0.2996 – P × 0.28 = 294 P × 0.0196 = 294 P = 294 ÷ 0.0196 = Rs. 15000 Therefore, required interest = 15000 × 10% × 2 = Rs. 3000
14 × 11 + 25 – ? = 21% of 300
Determine the value (6.375)2 - (3.125)2
What will come in place of the question mark (?) in the following expression?
(320 ÷ 8 + 22) × 4 = 60 + 40% of ?
350% of (450 / 1.5) = ?% of 4200
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
What will come in the place of question mark (?) in the given expression?
? = 70% of 36% of (25 × 320) + 150
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} What will come in the place of question mark (?) in the given expression?
√1936 + (84 ÷ 2 × 1.5) – 35² + 18² = ?
13/3 – (23/6) = ? – (22/9)
- 48% of 300 – 24% of 150 = 12% of ?
