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Let the sum invested = Rs. Y According to the question, (Y × 3 × 10) ÷ 100 = 6000 So, Y = (6000/0.3) = 20000 So, required amount received = 20000(1 + 8/100)2 = 20000(27/25)2 = Rs. 23328
If tan α = 1/2, tan β = 1/3, then find α + β.
If (sinθ+cosθ)/(sinθ-cosθ) = 2, then the value of sin4 θ is
If 3 tan X + cot X = 2√3, then find the value of 6 tan2 X + 2 cot2 X.
If A + B = 450 , then the value of 2(1 + tanA) (1 + tanB) is:
Simplify (cos13°+sin 13°) /(cos13°-sin13°)
If sin 23° = `12/13` , then tan 67° = ?
...Take θ = 450
sin2 4˚ + sin2 6˚ + sin2 8˚ + sin2 10˚ + ……… + sin2 86˚ =?