Question
Rs. 6500 is invested in scheme ‘A’ for 2 years and
Rs. 6500 is invested in scheme ‘B’ for 2 years. Scheme ‘A’ offers simple interest of 14% p.a. If the interest received from both the schemes are equal, then find the rate of simple interest (p.a.) offered by scheme ‘B’.Solution
Interest received from scheme ‘A’ = 6500 × 14 × 2 ÷ 100 = Rs. 1820 Let the rate of simple interest offered by scheme ‘B’ = ‘k%’ p.a. ATQ; 6500 × 2 × k ÷ 100 = 1820 Or, 130k = 1820 Or, k = (1820/130) = 14 So, rate of simple interest offered by scheme ‘B’ = 14% per annum.
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
Find the area between the lines 18x +12y = 108, 9x + 6y = 27, x - axis and y -axis.
If in two linear equations ax + by = c and dx + ey = f and a/d = b/e = c/f then, which of the following is true about the two equations?
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
The lines x + y = 9 and x - y = 3 intersect at point P. Find the coordinates of P.
Solve: (x/3) + (x/5) = 16
Find the value of 'a' and 'b' which satisfy the following equations:
9a + 7b = 30
4a - 5b = 62
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
Relevant for Exams:
