Question
A man deposited Rs. 7500 in a bank offering compound
interest of 10% p.a. compounded annually for first 2.5 years and after that simple interest of 12% p.a. for rest of the time. If at the end of two and half years, he withdrew Rs. 4528.75; then amount received by him at the end of 4 years will be:Solution
Amount left after two and half years = 1.05 × 1.10 × 1.10 × 7500 – 4528.75 = 9528.75 – 4528.75 = Rs. 5000 Amount received at the end of four years = 5000 + 5000 × 0.12 × 1.5 = Rs. 5900
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
Find the coefficient of x³ in (2x − 3)⁶.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
Find the value of 'x' and 'y' in the following equation:
7x - 2y = 46
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
