Question
A borrows Rs 7500 from B at 14% p.a
compound interest compounded annually. At the end of every year he pays Rs 2500 and at the end of 3rd years he pays all the amount, how much amount does he pay at the end of the 3rd year?Solution
At the end of the 1st year:
Amount = 7500 × 114% = Rs. 8550
Rest amount = 8550 – 2500 = Rs. 6050
At the end of 2nd year:
Amount = 6050 × 114% = Rs. 6897
Rest amount = 6897 – 2500 = Rs. 4397
At the end of 3rd year:
Amount = 4397 × 114% = Rs. 5012.58
More Simple and compound interest Questions
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
(124.99)² = ?
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
1224.86% of √6399.98 = (399.99/4.99)% of (? ÷ 6.91 + 39.87)Â
24.11% of 249.99 + √143.97 ÷ 12.02 = ?