A certain sum of money becomes 3 times of itself in 10 years at simple interest. In how many years does it become double of itself at the same rate of simple interest?
Let the principal = Rs. x, Amount = Rs. 3x, Time = 10 years ∴ Simple Interest = Rs. (3x – x) = Rs. 2x Rate = [(2x × 100)/(x × 10)]% p.a. = 20% p.a. Now, Principal = Rs. x, Amount = Rs.2x, Rate = 20%p.a. Simple Interest= Rs. (2x − x)= Rs. x ∴ Time =(x × 100)/(x × 20) = 5 years.
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
? + 96.18 – 15.02 = 118.98 + 31.09
23.95% of 274.99 - 34.99% of 120.01 = 19.95% of ?
15.001% of 799.99 - 3/11% of 1099.99 + 111.002 = ?
(4096)1/3 × 10.11 × 11.97 ÷ 24.32 = ?+ 15.022
(804/65) ÷ (11/798) × (129/131) = ?
(√ (5475.5) +√ (1024.2)) -√ (4095.8)÷ (√ (143.9)× √ (15.678)...
? = 44.78% of 839.91 – 48.12% of 774.89 + 55.77% of 1024.85
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125