Question
A certain sum of money becomes 3 times of itself in 10
years at simple interest. In how many years does it become double of itself at the same rate of simple interest?Solution
Let the principal = Rs. x, Amount = Rs. 3x, Time = 10 years ∴ Simple Interest = Rs. (3x – x) = Rs. 2x Rate = [(2x × 100)/(x × 10)]% p.a. = 20% p.a. Now, Principal = Rs. x, Amount = Rs.2x, Rate = 20%p.a. Simple Interest = Rs. (2x − x)= Rs. x ∴ Time = (x × 100)/(x × 20) = 5 years.
- Find the wrong number in the given number series.
5, 10, 20, 35, 80, 160 - Find the wrong number in the given number series.
2, 10, 12, 36, 38, 34 Find the wrong number in the given number series.
30, 17, 19, 30.5, 64, 164.5
121Â Â Â Â Â 127Â Â Â Â Â Â 133Â Â Â Â Â Â 142Â Â Â Â Â Â 160Â Â Â Â Â Â 206
...6.5, 11, 22, 25.5, 51, 54.5
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 123, 155, 198, 246, 301, 363Â
14, 16, 22, 46, 172, 886
12, 18, 40, 90, 270, 945
Find the wrong number, in the given number series,
1680, 840, 2520, 630, 3150, 475