Question
A certain sum of money becomes 3 times of itself in 40
years at simple interest. In how many years does it become double of itself at the same rate of simple interest?Solution
Let the principal = Rs. x, Amount = Rs. 3x, Time = 40 years ∴ Simple Interest = Rs. (3x – x) = Rs. 2x Rate = [(2x × 100)/(x × 40)]% p.a. = 5% p.a. Now, Principal = Rs. x, Amount = Rs.2x, Rate = 5%p.a. Simple Interest = Rs. (2x − x)= Rs. x ∴ Time = (x × 100)/(x × 5) = 20 years.
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