Question
If the simple interest on a certain sum of money for 13 months at 7*1/2% per annum exceeds the simple interest on the same sum for 7 months at 12*1/2% per annum by Rs. 42.50, then the sum of money (in Rs.) is.
Solution
Let the sum be x Using formula, I = PRT/100  we have, (x × 13/12  × 15/2)/100 - (x × 7/12  × 25/2)/100 = 42.50 ⇒ 65x/800 -  175x/2400 = 42.50 ⇒ (195x-175x)/2400 = 42.50 ⇒ 20x/2400 = 42.50 ⇒ x = (2400 × 42.50)/20 = 5,100 ∴ Required sum = Rs. 5,100
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