Question
If the simple interest on a certain sum of money for 13
months at 7*1/2% per annum exceeds the simple interest on the same sum for 7 months at 12*1/2% per annum by Rs. 42.50, then the sum of money (in Rs.) is.Solution
Let the sum be x Using formula, I = PRT/100 we have, (x × 13/12 × 15/2)/100 - (x × 7/12 × 25/2)/100 = 42.50 ⇒ 65x/800 - 175x/2400 = 42.50 ⇒ (195x-175x)/2400 = 42.50 ⇒ 20x/2400 = 42.50 ⇒ x = (2400 × 42.50)/20 = 5,100 ∴ Required sum = Rs. 5,100
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
- Find the value of the expression:
25 + 9 – 8 × [10 + 14 – 2 × (33 – 18)] Find the simplified value of the given expression:
8 of 7 ÷ 2 × 5² + √36 – 10(? + 180 + 13 × 6) ÷ 20 + 3.5 × 512 (1/3) = 82
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
What will come in the place of question mark (?) in the given expression?
? = (266 × 276) ÷ (114 × 161) × 17
Find the value of ‘y’ if (2/7) × y = 0.79 – 1.77 ÷ 3.
42 + 52% of 300 - ?% of 200 = 88
(12 × 8 + 7 ÷ 5) × 5 = ?
Relevant for Exams:
