Question
Suppose a man invested Rs.(4000 + 2a) in Mutual Fund 'X'
for 2 years and Rs. (3200 + 6a) in scheme 'Y' for 2 years and interest gets from Mutual Fund 'X' is Rs. 112 more than interest gets from Mutual Fund 'Y', then what will be the entire amount invested in Mutual Fund 'Y'. Pratik invested Rs. 6800 in a Mutual Fund 'X' for two years which offered S.I. at the rate of r% per annum and gets total interest of Rs. 2176. There is also another Mutual fund 'Y', which offered C.I annually at the rate of (r –6) %.Solution
ATQ, we can say that Rate in Scheme ‘X’ = R = [(2176 × 100)/(6800 × 2)] = 16% Rate in Scheme ‘Y’ = R – 6 = 16 – 6 = 10% Then, (4000 + 2a) × 2 × 0.16 – (3200 + 6a) × (1.12 – 1) = 112 (4000 + 2a) × 0.32 – (3200 + 6a) × 0.21 = 112 1280 + 0.64a – 672 – 1.26a = 112 0.62x = 496 a = 800 Amount invested in Scheme 'Y' = 3200 + (6 × 800) = Rs.8000
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